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Q.

What is the sum of all the positive integral divisors of the numbers 540?


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a

1680

b

1670

c

1660

d

1690 

answer is A.

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Detailed Solution

Given,
Total numbers = 540
We have factorize the number
540=2×2×3×3×3×5×1=22×33×51……
540=22×33×5    [Prime factors of 540]
Now, we calculate sum of divisors as,
=23-12-1×34-13-1×52-15-1
=7×80×242×4
=1680
So, sum of positive integral divisors is 1680.
Option 1 is Correct.
 
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