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Q.

What is the sum of first 30 natural numbers?


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a

465

b

410

c

420

d

455  

answer is A.

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Detailed Solution

The given natural numbers are 1,2,3……
The natural number form an AP with first term 1 and common difference 1.
So, we have,
a=1,d=1.
We know that sum of first n terms of an AP is given as,
Sn=n22a+n-1d.
Putting the value of a = 1 and d = 1, we get
Sn=n2[2×1+(n-1)×1] Sn=n2[2+n-1]  Sn=n(n+1)2   [1]
Substituting n=30 in [1], we get
 S100=30(30+1)2
S100=465 Therefore, the sum of the first 30 natural numbers is 465.
Hence, the correct option is 1.
 
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