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Q.

What is the sum of the first 51 terms of an AP whose second and third terms are 14 and 18 respectively?


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a

5610

b

5550

c

5500

d

5000 

answer is A.

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Detailed Solution

Given that the second and third term are 14 and 18 respectively.
Let the first term be a and the common difference be d.
Determining common difference:
d= a 3 a 2 d=1814 d=4
Formula used for nth term of A.P.:  a n =a+ n1 d Determining first term:
a n =a+(n1)d a 2 =a+(21)4 14=a+4 a=144 a=10
Formula used for sum of first n term of A.P.:
S n = n 2 [2a+(n1)d]
Determining the sum of 51 terms:
  S 51 = 51 2 [2×10+(511)4] S 51 = 51 2 [20+(50)4] = 51 2 [20+200] = 51 2 [220]  
S 51 =5610 Therefore, the sum of 51 terms is 5610.
Hence, option (1) is correct.
 
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