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Q.

What is the sum of the measures of interior angles of a polygon of n sides?


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a

2n right angles

b

(2n-2) right angles

c

2(n-2) right angles

d

2(n-4) right angles  

answer is C.

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Detailed Solution

It is given a polygon of n sides.
If a polygon has n sides, then it is divided into (n-2) triangles.
We know that the sum of the angles of triangle = 180°.
Therefore, the sum of the angles of n-2triangles = 180 × (n-2) 2 ×90° × (n-2) 2(n-2) right angles
So, sum of measures of interior angles of a polygon of n sides is 2(n-2) right angles.
Hence, the correct option is 3.
 

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What is the sum of the measures of interior angles of a polygon of n sides?