What is the the coordinates of the centroid of a triangle whose vertices are (-1, -3), (2, 1) and (8, -4)?

Given, The vertices coordinates are (-1, -3), (2, 1), and (8, - 4).

From this, we can write the x- coordinates: x₁ = -1, x₂ = 2, x₃ = 8

Similarly, for the y-coordinates: y₁ = - 3, y₂ = 1, y₃ = - 4

The formula to find the centroid of a triangle:

$\mathrm{G}=\left(\frac{{\mathrm{x}}_1+{\mathrm{x}}_2+{\mathrm{x}}_3 }{3}, \frac{{\mathrm{y}}_1+{\mathrm{y}}_2+{\mathrm{y}}_3}{3}\right)$

On Substitution, we get:

 $\mathrm{G}=\left(\frac{-1+2+8}{3},\frac{-3+1-4}{3}\right)$

$\mathrm{G}=\left(\frac{9}{3},\frac{-6}{3}\right)$

G = $(3,-2)$

Therefore, the centroid of a triangle, G = (3, - 2)