What is the total number of electrons present in 1.6 g of methane?

1 mole of CH₄ = 16 g
16 g of CH₄ contains 10 x 6.023 x 10²³ electrons
1.6 g of CH₄ contains $\frac{10}{16}\times 1.6\times 6.023\times {10}^{23}$
= 6.023 x 10²³ electrons