What is the total surface area of the cuboid (in m²) of length 14 cm, width 10 cm, and height 8 cm?

Given,

length (l) of the cuboid = 14 cm

width (w) of the cuboid = 10 cm

height (h) of the cuboid = 8 cm

The surface area of the cuboid = 2 (lw + wh +lh)

$$\begin{gathered} =2\left(14\times 10+10\times 8+14\times 8\right) \\ =2\left(140+80+112\right) \\ =2\times 332 \\ =664 {\mathrm{cm}}^2 \end{gathered}$$

Now, 1 m = 100 cm

${\left(1 m\right)}^2={\left(100 cm\right)}^2=10000 c{m}^2$

Therefore, the surface area of the cuboid $=664 c{m}^2=\frac{664}{10000}{m}^2=0.0664 m^2$