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Q.

What is the value of electron gain enthalpy of $N a^{+}$ for $I E_{1}$ of Na = 5.1eV?

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a

$+ 10.2 e V$

b

$- 5.1 e V$

c

$- 10.2 e V$

d

$+ 2.55 e V$

answer is A.

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Detailed Solution

$I E_{1} o f N a = - E l e c t r o n g a i n e n t h a l p y o f N a^{+}$

$= - 5.1 e V$

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