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What is the value of $g$ on the surface of moon?

(Given, $G = 6.67 \times 1 0^{- 11} {Nm}^{2} / {kg}^{2}, R = 1.74 \times 1 0^{6} m, M = 7.35 \times 1 0^{22} kg)$

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9.8 m / s^{2}

1.62 m / s^{2}

4.9 m / s^{2}

18.6 m / s^{2}

answer is B.

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Detailed Solution

The value of g on the surface of moon is

1.62 m / s^{2}

.
The acceleration due to gravity is given by,

g = GM / R^{2}

.
The universal gravitational constant,

G = 6.67 \times 1 0^{- 11} {Nm}^{2} / {kg}^{2}

.
The radius of the moon is

, R = 1.74 \times 1 0^{6} m

.
The mass of the moon,

M = 7.35 \times 1 0^{22} kg

.
The acceleration due to gravity on the surface of the moon, gm is

g_{m} = \frac{6.67 \times 10^{- 11} \times 7.35 \times 10^{22}}{{(1.74 \times 10^{6})}^{2}}

\Rightarrow g_{m} = 1.62 m / s^{2}

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