What is the value of n in the following half equation, Cr(OH)4−+OH−→CrO4−2+H2O+ne−?

The value of n in the given half-equation is:n = 3Detailed Explanation:We are given the half-equation: Cr(OH)4- + OH- → CrO42- + H2O + ne-.First, let's balance the equation in terms of oxygen atoms and hydrogen atoms:The left side has 4 hydroxide ions (OH-) attached to Cr, and one more OH- is added to the equation.On the right side, CrO42- contains 4 oxygen atoms, and H2O contains one oxygen atom.Now, balance the charge:On the left side, the charge is -1 from Cr(OH)4- and -1 from OH-, giving a total charge of -2.On the right side, CrO42- carries a -2 charge, while H2O is neutral.The number of electrons, n, required to balance the charge difference is 3. The charge on the left side is -2, and the right side is -2. To balance the equation, three electrons are required on the left side.ConceptIn redox reactions, the number of electrons (n) is required to balance the change in oxidation states and charges on both sides of the equation.In this case, three electrons are required to balance the charge between the reactant and product sides.Balancing oxidation states and charges is essential in determining the correct value of n.

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What is the value of n in the following half equation, Cr(OH)₄⁻+OH⁻→CrO₄⁻2+H₂O+ne⁻?

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answer is 3.

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Detailed Solution

The value of n in the given half-equation is:

n = 3

Detailed Explanation:

We are given the half-equation:
Cr(OH)₄^- + OH^- → CrO₄^2- + H₂O + ne^-.
First, let's balance the equation in terms of oxygen atoms and hydrogen atoms:
- The left side has 4 hydroxide ions (OH^-) attached to Cr, and one more OH^- is added to the equation.
- On the right side, CrO₄^2- contains 4 oxygen atoms, and H₂O contains one oxygen atom.
Now, balance the charge:
- On the left side, the charge is -1 from Cr(OH)₄^- and -1 from OH^-, giving a total charge of -2.
- On the right side, CrO₄^2- carries a -2 charge, while H₂O is neutral.
The number of electrons, n, required to balance the charge difference is 3. The charge on the left side is -2, and the right side is -2. To balance the equation, three electrons are required on the left side.

Concept

In redox reactions, the number of electrons (n) is required to balance the change in oxidation states and charges on both sides of the equation.
In this case, three electrons are required to balance the charge between the reactant and product sides.
Balancing oxidation states and charges is essential in determining the correct value of n.