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What is the wavelength (in m) of a particle of mass 6.62 × 10^–29 g moving with a velocity of 10³m.s^–1? (h = 6.62 × 10^–34 J.S)

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6.62 × 10^–4

10^–5

6.62 × 10^–3

10⁵

answer is D.

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Detailed Solution

$λ = \frac{h}{m v} = \frac{6.626 \times 10^{- 27}}{6.62 \times 10^{- 29} \times 10^{3}} = 10^{- 5}$

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