What is $\Delta U$ for the process described by figure. Heat supplied during the process $q=100kJ$.

 

$\Delta u=q+w$

W = under graph (work done by the gas=1)

$w=\frac{1}{2}\times 1\times \left(1+2\right)=\frac{3}{2}\times {10}^{5}N-m^2$

$\Delta U=100-\frac{3}{2}\times \frac{{10}^5}{1000}=100-150=-50kJ$