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What length of brass and iron at $00 C$ must be used if difference between their lengths is always $0.2 m$ ? $a b r = 18 × 10 − 6 / ° C, a i r o n = 12 × 10 − 16 / ° C$

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0.4 m, 0.6 m

0.4 m, 0.8 m

0.4 m, 0.3 m

0.6 m, 0.3 m

answer is A.

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Detailed Solution

α 1 l 1 = α 2 l 2 l 2 − l 1 = x ⇒ l 1 = α 2 x α 1 − α 2 = 0.4 m; l 2 = α 1 x α 1 − α 2 = 0.6 m

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