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What makes the following compound aromatic?

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Remove $H^{+}$ ion from $S P^{2}$ carbon

Add two electron to $π$ -bond to give $C_{9} H_{10}^{- 2}$

Remove $H^{+}$ ion, from $s p^{3}$ carbon

Add one electron to $π$ -bond to give $C_{9} H_{10}^{-}$

answer is C.

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Detailed Solution

Carbon forms carbanion, which comes in to conjugation, makes the compound aromatic.

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