What mass of octane should be taken in a total 100 gm mixture of octane and oxygen gas so as to obtain maximum ${CO}_{2}$ (g) on complete combustion?

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100 gm

50 gm

23.54 gm

22.17 gm

answer is D.

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Detailed Solution

In the following reaction,

$\begin{array}{l} C_{8} H_{18} + \frac{25}{2} O_{2} \to 8 {CO}_{2} + 9 H_{2} O \\ \frac{W}{114} \times \frac{25}{2} = \frac{(100 - W)}{32} \Rightarrow W = 22.17 g \end{array}$

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