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What mass of sodium chloride would be decomposed by 9.8 g of sulphuric acid, if 12 g of sodium bisulphate and 2.75 g of hydrogen chloride were produced in a reaction?

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1475 g

3.8 g

2.2 g

4.95 g

answer is C.

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Detailed Solution

$\underset{x g}{NaCl} + \underset{9.8 g}{H_{2} {SO}_{4}} \to \underset{12 g}{{NaHSO}_{4}} + \underset{2.75 g}{HCl}$
x + 9.8 = 12 + 2.75
x = 4.95 g

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