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Q.

What percentage T₁ is of T₂ for a l0% efficiency of a heat engine? T₁, is the temperature of sink and T₂ is the temperature of heat reservoir.

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a

$T_{1} = 90 % of T_{2}$

b

$T_{1} = T_{2}$

c

$T_{2} - 90 % of T_{1}$

d

$T_{1} = 50 % of T_{2}$

answer is A.

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Detailed Solution

$\begin{array}{l} Efficiency, η = \frac{T_{2} - T_{1}}{T_{2}} = 1 - \frac{T_{1}}{T_{2}} = 0.1 \\ or T_{1} = 0.9 T_{2} \end{array}$

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