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What should be the order $E_{1}, E_{2}, E_{3} & E_{4}$ if these are the respective energies of the first, second third and fourth orbits of hydrogen atom?

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$E_{1} = E_{2} = E_{3} = E_{4}$

$E_{4} < E_{3} < E_{2} < E_{1}$

$E_{2} > E_{3} < E_{4} < E_{1}$

$E_{1} < E_{2} < E_{3} < E_{4}$

answer is C.

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Detailed Solution

$E_{a} = E_{1} α \frac{22}{42}$

As n value increases the energy also increases.

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