What transition of Li²⁺ can emit a photon with same wave number as n = 2 to n = 1 transition of hydrogen atom

$$\begin{gathered} {\stackrel{-}{\mathrm{\nu }}}_{2\to 1}\left(\mathrm{H}\right)={\mathrm{R}}_{\mathrm{H}}\left(\frac{1}{1^2}-\frac{1}{2^2}\right)=\frac{3{\mathrm{R}}_{\mathrm{H}}}{4} \\ \left(\mathrm{A}\right) {\stackrel{-}{\mathrm{\nu }}}_{6\to 4}\left({\mathrm{Li}}^{+2}\right)={\mathrm{R}}_{\mathrm{H}}{3}^2\left(\frac{1}{4^2}-\frac{1}{6^2}\right)=\frac{5{\mathrm{R}}_{\mathrm{H}}}{16} \\ \left(\mathrm{B}\right) {\stackrel{-}{\mathrm{\nu }}}_{6\to 3}\left({\mathrm{Li}}^{+2}\right)={\mathrm{R}}_{\mathrm{H}}{3}^2\left(\frac{1}{3^2}-\frac{1}{6^2}\right)=\frac{3{\mathrm{R}}_{\mathrm{H}}}{4} \end{gathered}$$

Hence option(B) is the correct answer.