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What volume of 0.4M $N a_{2} S_{2} O_{3}$ required to react with the $I_{2},$ liberated by adding excess of KI to 50ml of 0.2M $C u S O_{4}$
$C u^{2 +} + I^{-} \to C u I + I_{2}$
$I_{2} + S_{2} {O_{3}}^{2 -} \to S_{4} {O_{6}}^{2 -} + I^{-}$

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25 ml

2.5ml

12.5 ml

50 ml

answer is B.

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Detailed Solution

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$I_{2} + N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6} + 2 N a I$
Eq.of $C u S o_{4} =$ eq. of $N a_{2} S_{2} O_{3}$
$0.2 \times 50 \times 1 = 0.4 \times 1 \times V$
$V = 25 m l$

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