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What volume of ${CO}_{2}$ will be liberated at STP if 12 g of carbon is burnt in excess of oxygen?

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11.35 L

2.27 L

22.7 L

1.135 L

answer is B.

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Detailed Solution

$\begin{array}{l} C (s) + O_{2} ⟶ C_{2} \\ 12 {gm}_{m} V (l) \\ \frac{12}{12} = \frac{v (l)}{22.7} \\ V (l) = 22.7 . \end{array}$

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