What weight of oxalic acid $({\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4.2{\mathrm{H}}_2\mathrm{O})$ is required to prepare 1,000 mL of N/10 solution?

 weight of oxalic acid$=\frac{\text{Mol.wt}}{\text{Basicity}}=\frac{\text{Mol.wt}}{2}=\frac{126}{2}=63$

Weight of oxalic acid required to prepare 1000 mL 

$\mathrm{N} =\frac{\mathrm{weight}}{\mathrm{Eqt}.\mathrm{Wt}}\times \frac{1000}{\mathrm{V}\left(\mathrm{In} \mathrm{ml}\right)}$

$\frac{1}{10}=\frac{\mathrm{Weight}}{63}\times \frac{1000}{1000}$

$\mathrm{Weight} =6.3 \mathrm{gr}$