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What will be change in molar Gibbs free energy of $H_{2} O (l) at 300 K$ constant temperature if it is compressed from 10 bar to 20 bar: $[1 bar L = 100 J]$

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$28 J / mol - K$

$18 J / mol - K$

$36 J / mol - K$

$10 J / mol - K$

answer is C.

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Detailed Solution

$Δ G = V Δ P \begin{array}{l} Δ G = \frac{18}{1000} (10) bar L \\ Δ G = 18 J / mol - K \end{array}$

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