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Q.

What will be e.m.f of the cell 2Ag++CuCu2++2Ag given 

EAg+/Ag0=+0.8V

ECu2+/Cu0=+0.3V

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a

+ 1.3V

b

– 0.6 V   

c

+0.5 V

d

– 1.1 V

answer is B.

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Detailed Solution

Ecell0=Ecathode0EAnode0

= 0.8 – 0.3 = + 0.5 V

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