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What will be formed in the following Kolbe’s electrolysis?

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2 – butane

I – butyne

2 – butyne

Both b and c

answer is C.

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Detailed Solution

     NaO
      │
 O=C      C=O
  │        │

CH3–C═C–CH3
│
ONa

────────────→ CH3–C≡C–CH3

This represents the sodium salt of 2,5-dimethylfuran-2,5-dione undergoing decarboxylation, giving 2-butyne (CH3–C≡C–CH3).

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