What will be magnitude of net magnetic field as shown in figure at point P. (Magnetic moment of small magnets are M and $\frac{4 M}{3 \sqrt{3}}$ respectively)
Given that $(\frac{μ_{0}}{4 π} \frac{M}{R^{3}} = B_{0})$

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$\sqrt{5} B_{0}$

$\sqrt{3} B_{0}$

$B_{0}$

None of these

answer is C.

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Detailed Solution

Magnetic field at P due to the magnet having magnetic moment $\frac{4 M}{3 \sqrt{3}} = \frac{μ_{0}}{4 π} \frac{2 \times \frac{4 M}{3 \sqrt{3}}}{{(\frac{2 M}{\sqrt{3}})}^{3}} = B_{0}$

Therefore $B_{P} = \sqrt{{B_{0}}^{2} + {B_{0}}^{2} + 2 \times B_{0} \times B_{0} \times \cos 60^{0}} = \sqrt{3} B_{0}$

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