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What will be the distance of the object when a concave mirror produces an image of magnification m ? The focal length of the mirror is f

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\frac{1}{m (m + f)}

(m - 1) f

\frac{f}{m (m - 1)}

(m + 1) f

answer is C.

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Detailed Solution

Given

m = \frac{- v}{u} \Rightarrow v = - mu

By mirror formula $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$= \frac{1}{- (mu)} + \frac{1}{u}$

$\Rightarrow \frac{1}{f} = \frac{1}{u} (- \frac{1}{m} + 1) (or) u = \frac{f}{m (m - 1)}$

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