What will be the area of canvas needed to make the tent, if a circus tent is cylindrical to a height of 3 m and conical above it, with its base radius as 52.5 m and the slant height of the conical portion as 53 m?

Cylinder: 

Radius of the cylinder, $R=52.5 \mathrm{m}$

Height of the cylinder, $H= 3 \mathrm{m}$

Cone: 

Radius of the cylinder, $r=52.5 \mathrm{m}$

Slant height, $l= 53 \mathrm{m}$

We know that, curved surface area of the cylinder = $2\pi rh$

And the curved surface area of the cone = $\pi rl$ 

The area of canvas needed to make the tent 

= Surface area of the tent 

= Curved surface area of the cylindrical portion + curved surface area of conical portion 

= $2\pi RH+\pi rl$ 

= $2\times \frac{22}{7}\times 52.5\times 3+\frac{22}{7}\times 52.5\times 53$

= $990+8745$ 

= $9735$ 

Hence, the total area of canvas required for making the tent is $9735 {\text{m}}^2$.