What will be the distance covered by a car in $6\frac{1}{4}$ hours if the car is moving at an average speed of $60\frac{2}{5}$ km/hr?

Given: Speed of the car = $\mathbf{60}\frac{\mathbf{2}}{\mathbf{5}}$ Km/hr

Total time taken = $\mathbf{6}\frac{\mathbf{1}}{\mathbf{4}}$ hrs

Now, we know that:

Distance = Speed $\times$Time

So, the distance covered by the car:

= Speed of car $\times$Total time

= $60\frac{2}{5} \times 6\frac{1}{4}$

Simplifying:

= $\frac{60\times 5 + 2}{5}\times \frac{6\times 4 + 1}{4}$ 

= $\frac{300 + 2}{5}\times \frac{24 + 1}{4}$ 

= $\frac{302}{5}\times \frac{25}{4}$ 

= $\frac{302}{1}\times \frac{5}{4}$ 

= $\frac{1510}{4}$  

= $\frac{755}{2}$ 

= $\mathbf{377}\frac{\mathbf{1}}{\mathbf{2}}$

Therefore, the distance traveled is $\mathbf{377}\frac{\mathbf{1}}{\mathbf{2}}$Km.