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Q.

What will be the effect of adding 100 mL of 10- 3 M HCl solution to a solution of HA having concentration 0.1 M? (Ka of HA = 10-5)

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a

Both degree of dissociation and pH will decrease

b

Degree of dissociation of HA will decrease, pH will remain constant

c

Neither pH nor degree of dissociation of HA will change. 

d

Degree of dissociation of HA will increase and pH decreases.

answer is C.

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Detailed Solution

H+HA=105×0.1=103M=H+HCl

Hence, neither pH nor a changes.Both pH and dissociation degree will be reduced.

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