What will be the energy loss per hour in the iron core of a transformer if the area of its hysteresis loop is equivalent to 2500 erg/cm3. The frequency of alternating current is 50 Hz. The mass of core is 10 kg and the density of iron is 7.5 g/cm3.

E=nAVt=nAmρ=50×250×10×36007.5×103=6×104J

What will be the energy loss per hour in the iron core of a transformer if the area of its hysteresis loop is equivalent to 2500 erg/cm3. The frequency of alternating current is 50 Hz. The mass of core is 10 kg and the density of iron is 7.5 g/cm3.

E=nAVt=nAmρ=50×250×10×36007.5×103=6×104J

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What will be the energy loss per hour in the iron core of a transformer if the area of its hysteresis loop is equivalent to 2500 erg/cm³. The frequency of alternating current is 50 Hz. The mass of core is 10 kg and the density of iron is 7.5 g/cm³.

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2 × 10² J

4 × 10³ J

6 × 10⁴ J

8 × 10⁵ J

answer is C.

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$E = nAVt = nA \frac{m}{ρ} = \frac{50 \times 250 \times 10 \times 3600}{7.5 \times 10^{3}} = 6 \times 10^{4} J$

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What will be the energy loss per hour in the iron core of a transformer if the area of its hysteresis loop is equivalent to 2500 erg/cm3. The frequency of alternating current is 50 Hz. The mass of core is 10 kg and the density of iron is 7.5 g/cm3.

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What will be the energy loss per hour in the iron core of a transformer if the area of its hysteresis loop is equivalent to 2500 erg/cm³. The frequency of alternating current is 50 Hz. The mass of core is 10 kg and the density of iron is 7.5 g/cm³.