What will be the height of the first floor if the pressure of water on the ground floor is $4 \times 10^{4} Pa$ and $10^{4} Pa$ on the first floor? (Density of water = 1000 $kg m^{- 3}$ and g = 10 $m s^{- 2}$ )

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3 m

6 m

2 m

5 m

answer is A.

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Detailed Solution

The height of the first floor will be

3 m

if the pressure of water on the ground floor is

4 \times 10^{4} Pa

and

10^{4} Pa

on the first floor
Pressure of water on the ground floor

(P_{1}

) = 40000 Pa
Pressure of water on the first floor

(P_{2}

) = 10000 Pa
Density of water = 1000

kg m^{- 3}

By using the relation,

P_{1} - P_{2} = ρgh

We get,

40000 - 10000 = 1000 \times 10 \times h

\frac{30000}{10000} = h

h = 3 m

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