What will be the length of fencing wire required to border twice the rectangular playground with dimensions $10m\times 20m$ twice?

Given:

A rectangular playground is given to us with dimensions: $10m\times 20m$

To find the length of fencing wire which will be required for the ground if the wire required is twice the boundary of the ground.

Now, we know that the perimeter of the rectangle is found by the following expression:

$P=2(length+breadth)$

Now, substituting the dimensions of the ground, we get:

$P=2(10+20) m$

Simplifying this, we get:

$P=2\left(30\right) m$

$P=60 m$

Thus, the boundary of the park is $60m$ long

The fencing wire required for the given park, $x$ is:

$x=2\times 60$

Simplifying this, we get:

$x=120m$

Thus, the length of wire required is $120m$

Hence option A is correct