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Q.

What will be the lengths of the arcs and area of the minor segment cut off from a circle of radius 12 cm by a chord 12cm long?


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a

62.85c m 2  , 13.05c m 2  

b

62.85c m 2  , 13.07c m 2  

c

62.80c m 2  , 13.07c m 2  

d

62.85c m 2  , 13.75c m 2   

answer is B.

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Detailed Solution

We have to find the lengths of the arcs and area of the minor segment cut off from a circle of radius 12 cm by a chord 12cm long.
Value of π= 22 7   Area of the minor segment = π r 2 × θ 360 ° 1 2 × r 2 ×sinθ  ,
Where, r is the radius.
Calculating the area of the minor segment,
Question ImageSuppose AB is the chord.
Joining A and B to O, we get an equilateral triangle OAB.
Area of the sector =π r 2 × θ 360 °    Where, ‘ θ   ’ is the angle of the sector and r is the radius.
Note that the angles are equal since,
θ= 60 °   = θ 360 0 ×π r 2 1 2 × r 2 ×sinθ = 60 0 360 0 ×π 12 2 1 2 × 12 2 ×sin 60 0 = 1 60 0 × 22 7 ×144 1 2 ×144× 3 2 =13.07  
Calculating the length of the arc cut off from the circle,
Length of the arc is =2πr× θ 360 °  
 Note that,
Length of arc= 2πr2πr θ 360 0  
     Put π= 22 7  and r=12cm  So, length of the larger arc= 2πr(1 θ 360 0 )  
=2× 22 7 ×12× 5 6  
=62.85 cm2
So, the length of the arc cut off from circle is 62.85c m 2   and the area of the minor segment is 13.07c m 2  .
Therefore, option 2 is correct.
 
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