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Q.

What will be the mass of one ${}^{12}C$ atom in gram?

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a

$2.227 \times 10^{- 20} g$

b

$1.9927 \times 10^{- 19} g$

c

$1.9927 \times 10^{- 23} g$

d

$2.227 \times 10^{- 23} g$

answer is B.

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Detailed Solution

$Mass of 1 atom of {}^{12}C = \frac{Atomic mass of C}{Avogadro's number}$

$= \frac{12 g}{6.022 \times 10^{23}}$

$= 1.9927 \times 10^{- 23} g$

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