What will be the measure of each exterior angle of a regular pentagon, hexagon, heptagon, and polygon of 15 sides?

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The exterior angle of a regular pentagon is 72°, the hexagon is 60°, the heptagon is 51.43°, and the polygon of 15 sides is 24°

The exterior angle of a regular pentagon is 70°, the hexagon is 60°, the heptagon is 51.43°, and the polygon of 15 sides is 24°

The exterior angle of a regular pentagon is 72°, the hexagon is 60°, the heptagon is 51.45°, and the polygon of 15 sides is 24°

The exterior angle of a regular pentagon is 72°, the hexagon is 60°, the heptagon is 51.43°, and the polygon of 15 sides is 12°

answer is A.

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Detailed Solution

We know
● The regular pentagons, hexagons, and heptagons are polygons and the sum of the exterior angle of the Polygon is 360°.
● The formula for the measure of each exterior angle of a regular Polygon =

\frac{360 °}{no . of sides of the polygon}

And,
⇒ No. of sides in the Pentagon is 5.
So, the measure of each exterior angle of a regular pentagon is =

\frac{360 °}{5} = 72 °

.
⇒ No. of sides in Hexagon is 6.
So, the measure of each exterior angle of a regular Hexagon is =

\frac{360 °}{6} = 60 °

.
⇒ No. of sides in Heptagon is 7.
So, the measure of each exterior angle of a regular heptagon is =

\frac{360 °}{7} = 51.43 °

.
⇒ No. of sides in Polygon with 15 sides is 15
So, the measure of each exterior angle of a regular pentagon is =

\frac{360 °}{15} = 24 °

.
Thus, the exterior angle of a regular pentagon is 72°, the hexagon is 60°, the heptagon is 51.43°, and the polygon of 15 sides is 24°.

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