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Q.

What will be the molality of a solution having $18 g$ of glucose (mol. wt. $= 180$ ) dissolved in $500 g$ of water

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a

$0.5 m$

b

$0.2 m$

c

$2 m$

d

$1 m$

answer is C.

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Detailed Solution

$m = \frac{w (solute) \times 1000}{M (solute) \times W (solvent in gm .)} = \frac{18 \times 1000}{180 \times 500} = 0.2 m$

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