What will be the molality of the solution, containing 18.25 g of HCI gas in 500 g of water?

$\mathrm{Molality} \left(\mathrm{m}\right)=\frac{ \mathrm{No}.\mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute} }{ \mathrm{Mass} \mathrm{of} \mathrm{solvent}(\mathrm{in} \mathrm{kg}) }$
$\mathrm{Molality} =\frac{{\mathrm{W}}_{\mathrm{B}}\times 1000}{{\mathrm{M}}_{\mathrm{B}}\times {\mathrm{W}}_{\mathrm{A}} (\mathrm{in} \mathrm{g}) }=\frac{18.25\times 1000}{36.5\times 500}=1 \mathrm{m}$
$\left(\because \mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{HCl}=36.5 \mathrm{g} {\mathrm{mol}}^{-}\right)$