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Q.

What will be the molarity of a solution, which contains 5.85g of $N a C l (s)$ per 500ml?

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a

${4 mol.L}^{- 1}$

b

${0.2 mol.L}^{- 1}$

c

${2 mol.L}^{- 1}$

d

${20 mol.L}^{- 1}$

answer is C.

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Detailed Solution

$M = \frac{5.85 \times 1000}{58.5 \times 500} {=0.2 mol.L}^{-1}$

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What will be the molarity of a solution, which contains 5.85g of NaCl(s) per 500ml?