AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

What will be the nature of the image formed when an object is placed at $4 cm$ in front of a concave mirror of focal length $12 cm$ ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Magnified

Virtual

Erect

All of the above

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The nature of the image formed will be magnified, virtual and erect when an object is placed at

4 cm

in front of a concave mirror of focal length

12 cm

.
Given,

u = - 4 cm

f = - 12 cm

(Negative: as the mirror is concave)
By using the mirror formula, we can calculate the position of the image by substituting the values of u and f which are

- 4

and

- 12

respectively.

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

\Rightarrow \frac{1}{(- 12)} = \frac{1}{v} + \frac{1}{(- 4)}

\Rightarrow \frac{1}{v} = \frac{1}{4} - \frac{1}{12}

\Rightarrow \frac{1}{v} = \frac{3 - 1}{12}

\Rightarrow \frac{1}{v} = \frac{1}{6}

\Rightarrow v = + 6 cm

+ ve

sign indicates that the image will be formed behind the mirror, so it will be a virtual image.
Now, substituting the values of

u

and

v

in the magnification formula we get,

m = - \frac{v}{u}

\Rightarrow m = - \frac{6}{- 4}

\Rightarrow m = + 1.5

(Magnified)
So, the image formed will be virtual, erect and magnified.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!