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what will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH in the ratio 2:1 by volume?

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0.4N

0.5 N

1.05 N

0.15 N

answer is B.

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Detailed Solution

$N_{R} = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}} = \frac{2 \times 0 .45 + 0 .6 \times 1}{3} = 0 .5$

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