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What will be the pH of an aqueous solution of 1.0M ammonium formate?
(Given: ${pK}_{a} of formic acid = 3 .8$ and ${pK}_{b} of {NH}_{3} = 4 .8$ , ${pK}_{w} = 14$ )

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7.5

3.4

6.5

10.2

answer is C.

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Detailed Solution

$pH = \frac{1}{2} ({pK}_{w} + {pK}_{a} - {pK}_{b}) = 6 .5$

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