What will be the ratio of the wavelength of the first line to that of the second line of Paschen series of H atom?

First time of paschen series ${\mathrm{n}}_{\mathrm{1}}=3,\hspace{0.17em}\hspace{0.17em}{\mathrm{n}}_{\mathrm{2}}=\mathrm{4}$
$$\begin{gathered} \frac{1}{{\mathrm{\lambda }}_1}=\text{R}\left[\frac{1}{9}-\frac{1}{16}\right] \\ \frac{1}{{\mathrm{\lambda }}_1}=\frac{7\text{R}}{144}{\mathrm{\lambda }}_1=\frac{144}{7\text{R}} \\ \mathrm{Second} \mathrm{line} \mathrm{of} \mathrm{paschen} \mathrm{series} {\text{n}}_{\text{1}}={\text{3,\hspace{0.17em}\hspace{0.17em}n}}_{\text{2}}=\text{5} \\ \frac{1}{{\mathrm{\lambda }}_2}=\text{R}\left[\frac{1}{9}-\frac{1}{25}\right] \\ \frac{1}{{\mathrm{\lambda }}_2}=\frac{16\text{\hspace{0.17em}R}}{225}{\mathrm{\lambda }}_2=\frac{225}{16\text{\hspace{0.17em}R}} \\ \boxed{\frac{{\mathrm{\lambda }}_1}{{\mathrm{\lambda }}_2}=\frac{144}{7\text{\hspace{0.17em}R}}\times \frac{16\text{\hspace{0.17em}R}}{225}=\frac{2304}{1575}=\frac{256}{175}} \end{gathered}$$