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Q.

What will be the value of 4 x 2 + y 2 +25 z 2 +4xy10yz20zx when x=4, y=3 and z=2?


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a

1

b

2

c

3

d

4 

answer is A.

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Detailed Solution

Given,
x=4, y=3 and z=2
We have to find the value of 4 x 2 + y 2 +25 z 2 +4xy10yz20zx .
We know that,
a+bc 2 = a 2 + b 2 + c 2 +2ab2bc2ca
Substituting the values of x, y, and z, we get,
4 x 2 + y 2 +25 z 2 +4xy10yz20zx = (2x) 2 + (y) 2 + (5z) 2 +2×2×xy2×y×5z2×5z×2x = 2x+y5z 2
Substituting the values of x = 4, y = 3, and z = 2 in the above equation: = (2×4+35×2) 2 = (8+310) 2 = (1110) 2 =1
So, the value of 4 x 2 + y 2 +25 z 2 +4xy10yz20zx when x=4,y=3, and z=2 is 1.
Therefore, option 1 is correct.
 
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