Q.

What will be the value of a3b 3 + 3bc 3 + ca 3 ?


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a

3(a3b)(3bc)(ca)

b

4(a3b)(3bc)(ca)

c

5(a3b)(3bc)(ca)

d

6(a3b)(3bc)(ca)  

answer is A.

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Detailed Solution

We have to find the value of a3b 3 + 3bc 3 + ca 3 .
Using the formula,
x 3 + y 3 + z 3 3xyz=(x+y+z)( x 2 + y 2 + z 2 xyyzzx )
And, the factorization of the sum of the cubes when their sum is zero, if x+y+z =0 then x 3 + y 3 + z 3 =3xyz .
Let x=a3b , y=3bc , z=ca x 3 + y 3 + z 3 =(x+y+z)( x 2 + y 2 + z 2 xyyzzx) Calculating x+y+z , =a3b+3bc+ca =0 Then,
3xyz =3(a3b)(3bc)(ca)
So, the value of a3b 3 + 3bc 3 + ca 3 is 3(a3b)(3bc)(ca) .
Therefore, option 1 is correct.
 
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