What will be the weight of CO having the same number of O-atoms as present in 22 g of ${\mathrm{CO}}_2$?

$\text{ Number of }\mathrm{O}\text{-atoms in }22 {\mathrm{gCO}}_2=2$

$\text{ Molar mass of }{\mathrm{CO}}_2=44 \mathrm{g} 44 \mathrm{g}=1 \mathrm{mol}$

                                       22 g= 0.5 mol

$1\text{ mole of }{\mathrm{CO}}_2\text{ contains }=2\times 6.023\times {10}^{23}\mathrm{O}\text{-atoms }$

$0.5\text{ mole of }{\mathrm{CO}}_2=6.023\times {10}^{23}\mathrm{O}\text{-atom }$

$\text{ Number of }\mathrm{O}\text{-atoms in }\mathrm{CO}=6.023\times {10}^{23}\text{ molecules of }\mathrm{CO}$

                                            = l mole of CO

$1\text{ mole of }\mathrm{CO}=6.023\times {10}^{23}\mathrm{O}\text{-atoms }$

Molar mass of CO = 12 + 16 = 28 g