What will happen during the electrolysis of aqueous solution of CuSO₄ by using platinum electrodes?

For electrolysis of aqueous solution of CuSO₄
                 $\begin{array}{r}{\mathrm{CuSO}}_4\left(\mathrm{aq}\right)⟶{\mathrm{Cu}}^{2+}+{\mathrm{SO}}_4^{2-}\\ {\mathrm{H}}_2\mathrm{O}⟶2{\mathrm{H}}^{+}+{\mathrm{O}}^{2-}\end{array}$
$\begin{array}{l} \mathrm{At} \mathrm{anode} \mathrm{ }2{\mathrm{O}}^{2-}⟶{\mathrm{O}}_2+2{\mathrm{e}}^{-}\\ \mathrm{At} \mathrm{cathode} { \mathrm{Cu}}^{2+}+2{\mathrm{e}}^{-}⟶\mathrm{Cu}\left(\mathrm{s}\right)\end{array}$