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What will happen if the solution of potassium chromate reacts with excess amount of nitric acid?

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Cr reduces in the oxidation state +3 from ${CrO}_{4}^{2 -}$

Cr oxidises in the oxidation state +7 from ${CrO}_{4}^{2 -}$

${Cr}^{+ 3}$ and ${Cr}_{2} O_{7}^{2 -}$ will be formed

${Cr}_{2} O_{7}^{2 -}$ and $H_{2} O$ will be formed

answer is D.

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Detailed Solution

Reaction when the solution of potassium chromate reacts with excess amount of nitric acid is given as,

${CrO}_{4}^{2 -} \underset{{OH}^{-}}{\overset{H^{+}}{⇄}} {Cr}_{2} O_{7}^{2 -}$

Thus, here ${Cr}_{2} O_{7}^{2 -}$ and $H_{2} O$ will be formed.

Thus, the correct option is D.

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