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What will happen to the volume of a bubble of air found under water in a lake, where the temperature is 15°C and the pressure is 1.5 atm, if the bubble then rises to the surface where the temperature is 25°C and the pressure is 1.0 atm?

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Its volume will become grater by a factor of 1.1

Its volume will become greater by a factor of 1.6

Its volume will become greater by a factor of 0.70

Its volume will become greater by a factor of 2.5

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \\ \frac{1.5 \times V}{288} = \frac{1 \times V_{2}}{298} \\ = 1.66 V \end{array}$

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