What wilt be the molarity of a solution, which contains 5.85 g of NaCl (s) per 500 mL?

I mole of NaCl contains= 58.5 g

$\text{ Molarity of a solution }=\frac{\frac{5.85}{58.5} \mathrm{mol}}{\frac{500}{1000} \mathrm{L}}$

$=\frac{0.1 \mathrm{mol}}{1/2 \mathrm{L}}=0.2 \mathrm{mol}/\mathrm{L}$